LESSON 88 OF 409 · CONDITIONAL STATEMENTS - CHALLENGES

Employee of the Year V2 - Project in C++

Practice

Two employees are up for the Employee of the Year award. Pick the more productive one and compute their 15% bonus.

You start with:

string name1 = "John Doe";
int productivity1 = 83;
int salary1 = 135000;
string name2 = "Mary Jane";
int productivity2 = 133;
int salary2 = 335000;

Build:

Mary Jane
Bonus: $50250

Rules:

The winner is whichever employee has the higher productivity.
If both have the same productivity, employee 1 (the one listed first) wins.
The winner's bonus is 15% of their salary, rounded down to a whole number.
Print the winner's name on the first line, then "Bonus: $<amount>" on the second.

Declare string winnerName; int winnerSalary; before the if, then use if/else to assign them, so both are still in scope for the prints. A tie goes to employee 1, so compare with >=.

Dividing two int values drops the fraction, so winnerSalary * 15 / 100 is already rounded down: int bonus = winnerSalary * 15 / 100;

Chain the text and the number with <<: cout << "Bonus: $" << bonus << endl;

string name1 = "John Doe";
int productivity1 = 83;
int salary1 = 135000;
string name2 = "Mary Jane";
int productivity2 = 133;
int salary2 = 335000;

string winnerName;
int winnerSalary;
if (productivity1 >= productivity2) {
    winnerName = name1;
    winnerSalary = salary1;
} else {
    winnerName = name2;
    winnerSalary = salary2;
}
int bonus = winnerSalary * 15 / 100;
cout << winnerName << endl;
cout << "Bonus: $" << bonus << endl;

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Employee of the Year V2 - Project in C++

Employee Of The Year V2 in C++