LESSON 90 OF 404 · CONDITIONAL STATEMENTS - CHALLENGES

Employee of the Year V2 - Project in Go

Practice

Two employees are up for the Employee of the Year award. Pick the more productive one and compute their 15% bonus.

You start with:

name1 := "John Doe"
productivity1 := 83
salary1 := 135000
name2 := "Mary Jane"
productivity2 := 133
salary2 := 335000

Build:

Mary Jane
Bonus: $50250

Rules:

The winner is whichever employee has the higher productivity.
If both have the same productivity, employee 1 (the one listed first) wins.
The winner's bonus is 15% of their salary, rounded down to a whole number.
Print the winner's name on the first line, then "Bonus: $<amount>" on the second.

Declare var winnerName string; var winnerSalary int before the if, then use if/else to assign them, so both are still in scope for the prints. A tie goes to employee 1, so compare with >=.

Dividing two whole numbers (int) drops the fraction, so winnerSalary * 15 / 100 is already rounded down: bonus := winnerSalary * 15 / 100

Join text and a number with strconv.Itoa: fmt.Println("Bonus: $" + strconv.Itoa(bonus))

name1 := "John Doe"
productivity1 := 83
salary1 := 135000
name2 := "Mary Jane"
productivity2 := 133
salary2 := 335000

var winnerName string
var winnerSalary int
if productivity1 >= productivity2 {
    winnerName = name1
    winnerSalary = salary1
} else {
    winnerName = name2
    winnerSalary = salary2
}
bonus := winnerSalary * 15 / 100
fmt.Println(winnerName)
fmt.Println("Bonus: $" + strconv.Itoa(bonus))

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Guided

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Employee of the Year V2 - Project in Go

Employee Of The Year V2 in Go