LESSON 91 OF 404 · CONDITIONAL STATEMENTS - CHALLENGES

Employee of the Year V3 - Project in Go

Practice

Three employees compete for the award. Use a chained if / else if / else to pick the most productive one and print their 15% bonus.

You start with:

name1 := "John Doe"
productivity1 := 83
salary1 := 135000
name2 := "Mary Jane"
productivity2 := 133
salary2 := 335000
name3 := "Bob Smith"
productivity3 := 97
salary3 := 210000

Build:

Mary Jane
Bonus: $50250

Rules:

The winner is whichever of the three employees has the highest productivity.
If two or more employees share the highest productivity, the one listed first wins.
The winner's bonus is 15% of their salary, rounded down to a whole number.
Print the winner's name on the first line, then "Bonus: $<amount>" on the second.

Declare var winnerName string; var winnerSalary int before the if, then use an if / else if / else chain to assign them, so both are still in scope for the prints. Employee 1 wins when its productivity is at least that of both others; if not, employee 2 wins when it is at least employee 3's; otherwise employee 3 wins.

Dividing two whole numbers (int) drops the fraction, so winnerSalary * 15 / 100 is already rounded down: bonus := winnerSalary * 15 / 100

Join text and a number with strconv.Itoa: fmt.Println("Bonus: $" + strconv.Itoa(bonus))

name1 := "John Doe"
productivity1 := 83
salary1 := 135000
name2 := "Mary Jane"
productivity2 := 133
salary2 := 335000
name3 := "Bob Smith"
productivity3 := 97
salary3 := 210000

var winnerName string
var winnerSalary int
if productivity1 >= productivity2 && productivity1 >= productivity3 {
    winnerName = name1
    winnerSalary = salary1
} else if productivity2 >= productivity3 {
    winnerName = name2
    winnerSalary = salary2
} else {
    winnerName = name3
    winnerSalary = salary3
}
bonus := winnerSalary * 15 / 100
fmt.Println(winnerName)
fmt.Println("Bonus: $" + strconv.Itoa(bonus))

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Guided

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Employee of the Year V3 - Project in Go

Employee Of The Year V3 in Go