Build a tiny version of the Unix tr command. Given a list of lines and two single characters fromChar and toChar, replace every occurrence of fromChar with toChar in each line, then return the lines joined by newline characters (\n).
Notes: fromChar and toChar are single ASCII characters, taken literally (no escapes like \, no ranges). Upper and lower case are different characters. A line may be empty, and may not contain fromChar at all.
Function signature:
func tr(lines []string, fromChar string, toChar string) string
Example:
Input: lines = ["banana", "apple"], fromChar = "a", toChar = "X" Output: "bXnXnX\nXpple" When printed: bXnXnX Xpple
Go's
strings.ReplaceAll(s, old, new) swaps EVERY occurrence. Collect the translated lines into a []string and join them with strings.Join(result, "\n").
The full solution:
func tr(lines []string, fromChar string, toChar string) string {
result := []string{}
for _, line := range lines {
result = append(result, strings.ReplaceAll(line, fromChar, toChar))
}
return strings.Join(result, "\n")
}
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