Build a tiny version of the Unix grep command. Given a list of lines and a search pattern, return all lines that contain pattern as a substring (case-sensitive), joined by newline characters (\n).
Function signature:
public String grep(List<String> lines, String pattern)
Example:
Input: pattern = "err" lines = ["error: foo", "warning", "another error", "ok"] Output: "error: foo\nanother error" When printed: error: foo another error
If no lines match, return the empty string "".
Note: real grep treats the pattern as a regular expression by default (grep -F matches plain text). Here the pattern is always plain text: just look for it literally, so characters such as . or * mean nothing special.
Iterate over the lines, keep the ones where
line.contains(pattern) is true, then String.join("\n", result).
The full solution:
class Solution {
public String grep(List<String> lines, String pattern) {
List<String> result = new ArrayList<>();
for (String line : lines) {
if (line.contains(pattern)) {
result.add(line);
}
}
return String.join("\n", result);
}
}
Free plan: 30 tutor messages. Premium is unlimited.
