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LESSON 190 OF 410 · NESTED LOOPS

Top K Brands V5 - Filter by Product in Java

Practice

The full catalog covers many products. Filter to one product first, then rank the top k brands that sell it, using v4's repeated search on the filtered lists.

You start with:

String[] products = {"Laptop", "Phone", "Laptop", "Tablet", "Phone", "Laptop"};
String[] brands = {"TechPro", "MegaCorp", "NeoByte", "Quantum", "Zenith", "AlphaTech"};
int[] ratings = {4, 5, 5, 3, 4, 4};
String target = "Laptop";
int k = 2;

Build:

1. NeoByte (5)
2. TechPro (4)

Rules:

  • Filter: copy the brand and the rating of every row whose product equals target into two new lists, keeping the order.
  • From the filtered lists pick the top k by rating, highest first, with v4's repeated search. Ties go to the entry listed first.
  • If fewer than k products match, list only those that exist: when no brand is left, add no more lines (no extra lines, no error).
  • Each line is "rank. Brand (rating)", starting at rank 1.
  • Print the lines, one per line, with System.out.println(...).

Build filteredBrands and filteredRatings first: a loop over the catalog that copies the row when products[i].equals(target).

Then run v4's repeated search over the filtered lists (same code, new names).

If fewer than k products match, some round finds nobody (bestIndex stays -1): add a line only when a brand was found.

String[] products = {"Laptop", "Phone", "Laptop", "Tablet", "Phone", "Laptop"};
String[] brands = {"TechPro", "MegaCorp", "NeoByte", "Quantum", "Zenith", "AlphaTech"};
int[] ratings = {4, 5, 5, 3, 4, 4};
String target = "Laptop";
int k = 2;

List<String> filteredBrands = new ArrayList<>();
List<Integer> filteredRatings = new ArrayList<>();
for (int i = 0; i < products.length; i++) {
    if (products[i].equals(target)) {
        filteredBrands.add(brands[i]);
        filteredRatings.add(ratings[i]);
    }
}
boolean[] used = new boolean[filteredRatings.size()];
List<String> lines = new ArrayList<>();
for (int rank = 1; rank <= k; rank++) {
    int bestIndex = -1;
    for (int i = 0; i < filteredRatings.size(); i++) {
        if (!used[i]) {
            if (bestIndex == -1 || filteredRatings.get(i) > filteredRatings.get(bestIndex)) {
                bestIndex = i;
            }
        }
    }
    if (bestIndex != -1) {
        used[bestIndex] = true;
        lines.add(rank + ". " + filteredBrands.get(bestIndex) + " (" + filteredRatings.get(bestIndex) + ")");
    }
}
System.out.println(String.join("\n", lines));

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    Top K Brands V5 in Java

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