LRU Cache in Kotlin in Kotlin

A cache keeps a few recent results close at hand so they are quick to read again. It can only hold a limited number of entries, so when it is full it must throw one away. An LRU (Least Recently Used) cache throws away the entry that was used longest ago. Build a class LRUCache that stores integer keys with integer values.

The class keeps: private val capacity: Int (declared in the class header), a MutableMap<Int, Int> called map (key to value) and a MutableList<Int> called order (the keys, least recently used first).

Create it: LRUCache(capacity) makes an empty cache that holds at most capacity entries.

Methods and rules:

• fun get(key: Int): Int returns the value stored for key. A hit counts as a use: the key becomes the most recently used. If the key is not in the cache (never stored, or already evicted), return -1 and change nothing.
• fun put(key: Int, value: Int) stores the value for key, and the key becomes the most recently used.
  • If the key is already in the cache, replace its value. Nothing is evicted.
  • If the key is new and the cache already holds capacity entries, first evict the least recently used entry (remove it from the map and from order), then store the new one.
• Keep order sorted by use: the least recently used key at the front, the most recently used at the end. Every use moves the key to the end.

Tools for this language:

• The primary constructor is the class header: class LRUCache(private val capacity: Int). The fields are mutableMapOf() and mutableListOf().
• map.containsKey(key) tells whether a key is stored; map[key] = value stores or replaces a value; map.remove(key) deletes an entry; map.size counts the entries.
• order.remove(key) removes an item by value (the list holds Int), order.add(key) adds at the end, and order[0] with order.removeAt(0) reads and removes the first item.

This version walks over the list of keys for each operation, which is fine for learning. Interview solutions reach O(1) with a hash map plus a doubly linked list.

You start with the code that tests your class (write LRUCache above it):

class Solution {
    fun mainFunction() {
        val c = LRUCache(2)
        c.put(1, 10)
        c.put(2, 20)
        println("Get 1: " + c.get(1))
        c.put(3, 30)
        println("Get 2: " + c.get(2))
        println("Get 3: " + c.get(3))
        println("Miss 9: " + c.get(9))
        c.put(1, 11)
        println("Update 1: " + c.get(1))
        c.put(4, 40)
        println("Evicted 3: " + c.get(3))
        println("Kept 1: " + c.get(1))
        println("Kept 4: " + c.get(4))
        val s = LRUCache(1)
        s.put(1, 100)
        s.put(2, 200)
        println("Small 1: " + s.get(1))
        println("Small 2: " + s.get(2))
    }
}

Expected output:

Get 1: 10
Get 2: -1
Get 3: 30
Miss 9: -1
Update 1: 11
Evicted 3: -1
Kept 1: 11
Kept 4: 40
Small 1: -1
Small 2: 200

Check it against the rules: Get 2 is -1 because key 2 was the least recently used when key 3 arrived (key 1 had just been read). Updating key 1 to 11 does not evict anything. With capacity 1, the second put evicts the first key.