LESSON 93 OF 410 · CONDITIONAL STATEMENTS - CHALLENGES

Employee of the Year V2 - Project in Python

Practice

Two employees are up for the Employee of the Year award. Pick the more productive one and compute their 15% bonus.

You start with:

name1 = "John Doe"
productivity1 = 83
salary1 = 135000
name2 = "Mary Jane"
productivity2 = 133
salary2 = 335000

Build:

Mary Jane
Bonus: $50250

Rules:

The winner is whichever employee has the higher productivity.
If both have the same productivity, employee 1 (the one listed first) wins.
The winner's bonus is 15% of their salary, rounded down to a whole number.
Print the winner's name on the first line, then "Bonus: $<amount>" on the second.

Use if/else to pick the winner. Store both their name and their salary (winner_name, winner_salary) in every branch, so the bonus formula stays simple. A tie goes to employee 1, so compare with >=.

Use integer division // so the bonus stays a whole number: bonus = winner_salary * 15 // 100.

Joining text and a number needs str(): print("Bonus: $" + str(bonus))

name1 = "John Doe"
productivity1 = 83
salary1 = 135000
name2 = "Mary Jane"
productivity2 = 133
salary2 = 335000

if productivity1 >= productivity2:
    winner_name = name1
    winner_salary = salary1
else:
    winner_name = name2
    winner_salary = salary2
bonus = winner_salary * 15 // 100
print(winner_name)
print("Bonus: $" + str(bonus))

STEP 1 OF 7

Guided

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Employee of the Year V2 - Project in Python

Employee Of The Year V2 in Python