LESSON 155 OF 410 · LOOPING OVER LIST INDICES

Employee of the Year V4 - Project in Python

Practice

A whole team is competing. Use a for loop over the lists to find the most productive employee, then print their 15% bonus.

You start with:

names = ["John Doe", "Mary Jane", "Bob Smith", "Alice Chen", "Carlos Diaz"]
productivities = [83, 133, 97, 150, 120]
salaries = [135000, 335000, 210000, 250000, 180000]

Build:

Alice Chen
Bonus: $37500

Rules:

Index i in all three lists refers to the same employee.
The winner is whichever employee has the highest productivity. If two employees share the highest productivity, the one listed first wins.
The winner's bonus is 15% of their salary, rounded down to a whole number.
Print the winner's name on the first line, then "Bonus: $<amount>" on the second.

Start with best_index = 0 and loop over the other indices with for i in range(1, len(names)). Inside the loop, update the best index only when productivities[i] > productivities[best_index]: a strict comparison keeps the first employee on a tie.

Use integer division // so the bonus stays a whole number: bonus = salaries[best_index] * 15 // 100.

Joining text and a number needs str(): print("Bonus: $" + str(bonus))

names = ["John Doe", "Mary Jane", "Bob Smith", "Alice Chen", "Carlos Diaz"]
productivities = [83, 133, 97, 150, 120]
salaries = [135000, 335000, 210000, 250000, 180000]

best_index = 0
for i in range(1, len(names)):
    if productivities[i] > productivities[best_index]:
        best_index = i
bonus = salaries[best_index] * 15 // 100
print(names[best_index])
print("Bonus: $" + str(bonus))

STEP 1 OF 6

Guided

Ctrl + Enter to check

Employee of the Year V4 - Project in Python

Employee Of The Year V4 in Python