LESSON 188 OF 410 · NESTED LOOPS

Employee of the Year V6 - Project in Python

Practice

Generalize the previous version: give bonuses to the top K most productive employees, where k is given as a variable. Still no sorting: repeat the search for the best employee k times, and remember who already won so nobody wins twice.

You start with:

names = ["John Doe", "Mary Jane", "Bob Smith", "Alice Chen", "Carlos Diaz"]
productivities = [83, 133, 97, 150, 120]
salaries = [135000, 335000, 210000, 250000, 180000]
k = 3

Build:

Alice Chen: $37500
Mary Jane: $50250
Carlos Diaz: $27000

Rules:

Index i in all three lists refers to the same employee.
Round 1 finds the employee with the highest productivity, round 2 the best among the employees who have not won yet, and so on, for k rounds.
If two employees have the same productivity, the one listed first wins.
Each bonus is 15% of the salary, rounded down (using //).
Print one line per winner, best first: name: $bonus.
If k is larger than the number of employees, everybody wins once and you print one line per employee: when nobody is left, a round prints nothing.
Your code must keep working when k changes to 1, 2, 5 or 7.

Use a list of booleans: taken = [False] * len(names). A round finds the best employee among those who are not taken yet, then marks that employee as taken.

The outer loop runs k times and the inner loop is the search from v4 with one more condition: if not taken[i] and (best_index == -1 or productivities[i] > productivities[best_index]):. If nobody is found in a round, skip the rest of that round.

names = ["John Doe", "Mary Jane", "Bob Smith", "Alice Chen", "Carlos Diaz"]
productivities = [83, 133, 97, 150, 120]
salaries = [135000, 335000, 210000, 250000, 180000]
k = 3

taken = [False] * len(names)
for rank in range(k):
    best_index = -1
    for i in range(len(names)):
        if not taken[i] and (best_index == -1 or productivities[i] > productivities[best_index]):
            best_index = i
    if best_index != -1:
        taken[best_index] = True
        bonus = salaries[best_index] * 15 // 100
        print(names[best_index] + ": $" + str(bonus))

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Employee of the Year V6 - Project in Python

Employee Of The Year V6 in Python