Rank the top k brands by rating, breaking ties with the review count. This builds on v4's repeated search (not on v5: there is no filtering here); only the comparison gets a second criterion.
You start with:
brands = ["TechPro", "MegaCorp", "NeoByte", "Quantum", "Zenith"]
ratings = [4, 5, 5, 3, 4]
reviews = [200, 150, 500, 100, 300]
k = 3
Build:
1. NeoByte (5, 500) 2. MegaCorp (5, 150) 3. Zenith (4, 300)
Rules:
- Rating decides first: the higher rating wins.
- If two brands have the same rating, the one with more reviews wins.
- If rating and reviews are both equal, the one listed first wins (the test data has no such pair, but your code must follow the rule).
kis never larger than the number of brands.- Each line is
"rank. Brand (rating, reviews)", starting at rank 1. - Join the lines with
"\n"and store the text inoutput(the site prints it for you).
Start from v4: the same
used = [False] * len(ratings) and lines = [], the same two loops. Only the comparison inside the inner loop changes.
Use a chain (if / elif / elif): no candidate yet, take this one; else a higher rating, take this one; else the same rating and more reviews, take this one.
brands = ["TechPro", "MegaCorp", "NeoByte", "Quantum", "Zenith"]
ratings = [4, 5, 5, 3, 4]
reviews = [200, 150, 500, 100, 300]
k = 3
used = [False] * len(ratings)
lines = []
for rank in range(1, k + 1):
best_index = -1
for i in range(len(ratings)):
if not used[i]:
if best_index == -1:
best_index = i
elif ratings[i] > ratings[best_index]:
best_index = i
elif ratings[i] == ratings[best_index] and reviews[i] > reviews[best_index]:
best_index = i
used[best_index] = True
lines.append(str(rank) + ". " + brands[best_index] + " (" + str(ratings[best_index]) + ", " + str(reviews[best_index]) + ")")
output = "\n".join(lines)
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