Use a dictionary, a loop, and conditionals to print each subject with its letter grade in alphabetical order.
You start with:
var grades = [String: Int]()
grades["Math"] = 92
grades["English"] = 78
grades["Science"] = 85
grades["History"] = 67
Build:
English: C History: D Math: A Science: B
Rules:
- Visit the subjects in alphabetical order.
- Look up each subject's score in the dictionary and apply the grading scale (90+ A, 80s B, 70s C, 60s D, else F).
- On each iteration print the subject, a colon and a space, then the grade, for example
English: C.
Use a
[String: Int] dictionary and iterate with grades.keys.sorted() - it gives keys in sorted order.
var grades = [String: Int]()
grades["Math"] = 92
grades["English"] = 78
grades["Science"] = 85
grades["History"] = 67
for subject in grades.keys.sorted() {
let score = grades[subject]!
var grade = ""
if score >= 90 {
grade = "A"
} else if score >= 80 {
grade = "B"
} else if score >= 70 {
grade = "C"
} else if score >= 60 {
grade = "D"
} else {
grade = "F"
}
print("\(subject): \(grade)")
}
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