Show the top k brands by rating. This is v3's search, repeated k times: find the best brand, mark it as taken, then search again among the brands that are not taken yet, until you have k brands in rank order.
You start with:
let brands = ["TechPro", "MegaCorp", "Quantum", "NeoByte", "Zenith"]
let ratings = [4, 5, 3, 5, 4]
let k = 3
Build:
1. MegaCorp (5) 2. NeoByte (5) 3. TechPro (4)
Rules:
- Repeat v3's search
ktimes. Each round looks only at brands that are not taken yet and picks the one with the highest rating, then marks it as taken (one true/false flag per brand). - Ties go to the brand listed first: keep the first brand you find and replace it only on a strictly higher rating.
kis never larger than the number of brands.- Each line is
"rank. Brand (rating)", starting at rank 1. - Print the lines, one per line, with
print(...).
Start with the two declarations
var used = Array(repeating: false, count: ratings.count) and var lines = [String](). A flag tells whether that position is already taken.
Each round is v3's search: nothing found yet, scan every position, skip taken ones, keep the first candidate and replace it only on a strictly higher rating. Then mark the winner as taken and add its line.
let brands = ["TechPro", "MegaCorp", "Quantum", "NeoByte", "Zenith"]
let ratings = [4, 5, 3, 5, 4]
let k = 3
var used = Array(repeating: false, count: ratings.count)
var lines = [String]()
for rank in 1...k {
var bestIndex = -1
for index in ratings.indices {
if !used[index] {
if bestIndex == -1 || ratings[index] > ratings[bestIndex] {
bestIndex = index
}
}
}
used[bestIndex] = true
lines.append("\(rank). \(brands[bestIndex]) (\(ratings[bestIndex]))")
}
print(lines.joined(separator: "\n"))
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