LESSON 97 OF 414 · CONDITIONAL STATEMENTS - CHALLENGES

Employee of the Year V3 - Project in TypeScript

Practice

Three employees compete for the award. Use a chained if / else if / else to pick the most productive one and print their 15% bonus.

You start with:

const name1: string = "John Doe";
const productivity1: number = 83;
const salary1: number = 135000;
const name2: string = "Mary Jane";
const productivity2: number = 133;
const salary2: number = 335000;
const name3: string = "Bob Smith";
const productivity3: number = 97;
const salary3: number = 210000;

Build:

Mary Jane
Bonus: $50250

Rules:

The winner is whichever of the three employees has the highest productivity.
If two or more employees share the highest productivity, the one listed first wins.
The winner's bonus is 15% of their salary, rounded down to a whole number.
Print the winner's name on the first line, then "Bonus: $<amount>" on the second.

Declare let winnerName: string, winnerSalary: number; before the if, then use an if / else if / else chain to assign them, so both are still in scope for the prints. Employee 1 wins when its productivity is at least that of both others; if not, employee 2 wins when it is at least employee 3's; otherwise employee 3 wins.

Use Math.floor to round the 15% down to a whole number: const bonus: number = Math.floor(winnerSalary * 15 / 100);

+ turns the number into text: console.log("Bonus: $" + bonus);

const name1: string = "John Doe";
const productivity1: number = 83;
const salary1: number = 135000;
const name2: string = "Mary Jane";
const productivity2: number = 133;
const salary2: number = 335000;
const name3: string = "Bob Smith";
const productivity3: number = 97;
const salary3: number = 210000;

let winnerName: string, winnerSalary: number;
if (productivity1 >= productivity2 && productivity1 >= productivity3) {
    winnerName = name1;
    winnerSalary = salary1;
} else if (productivity2 >= productivity3) {
    winnerName = name2;
    winnerSalary = salary2;
} else {
    winnerName = name3;
    winnerSalary = salary3;
}
const bonus: number = Math.floor(winnerSalary * 15 / 100);
console.log(winnerName);
console.log("Bonus: $" + bonus);

STEP 1 OF 13

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Employee of the Year V3 - Project in TypeScript

Employee Of The Year V3 in TypeScript