LESSON 178 OF 414 · PROJECTS: EVERYDAY PROGRAMS

Report Card V5 - Subject to Grade Dictionary in TypeScript

Practice

Use a dictionary, a loop, and conditionals to print each subject with its letter grade in alphabetical order.

You start with:

const grades: Record<string, number> = {"Math": 92, "English": 78, "Science": 85, "History": 67};

Build:

English: C
History: D
Math: A
Science: B

Rules:

Visit the subjects in alphabetical order.
Look up each subject's score in the dictionary and apply the grading scale (90+ A, 80s B, 70s C, 60s D, else F).
On each iteration print the subject, a colon and a space, then the grade, for example English: C.

Object.keys(grades).sort() gives the keys alphabetically.

const grades: Record<string, number> = {"Math": 92, "English": 78, "Science": 85, "History": 67};

const subjects: string[] = Object.keys(grades).sort();
for (const subject of subjects) {
    const score: number = grades[subject];
    let grade: string;
    if (score >= 90) {
        grade = "A";
    } else if (score >= 80) {
        grade = "B";
    } else if (score >= 70) {
        grade = "C";
    } else if (score >= 60) {
        grade = "D";
    } else {
        grade = "F";
    }
    console.log(subject + ": " + grade);
}

STEP 1 OF 10

Guided

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Report Card V5 - Subject to Grade Dictionary in TypeScript

Report Card V5 in TypeScript