TL ; DR:
Go controls access through identifier capitalization. Lowercase names are unexported (package-private); uppercase names are exported (publicly visible). There are no
public/privatekeywords.Unexported fields are hidden from code outside the package:
type Dog struct { name string // unexported — hidden outside the package } func NewDog(name string) Dog { return Dog{name: name} } func (d Dog) getName() string { return d.name }
Outside the package,
rex.nameis a compile error. Userex.getName()instead.
Full lesson:
Access control in Go uses identifier capitalization instead of explicit access keywords — lowercase identifiers are package-private (unexported), uppercase identifiers are public (exported).
type BankAccount struct {
balance float64 // unexported — hidden outside the package
}
func (b *BankAccount) deposit(amount float64) {
if amount < 0 { return }
b.balance += amount
}
func (b BankAccount) getBalance() float64 { return b.balance }
If balance were exported (written as Balance), any client could just write account.Balance = -1000 and corrupt the state.
Your task
The Dog struct has its name field unexported (lowercase). Add a getName() method that returns name.
Dog's name: RexFree plan: 30 tutor messages. PRO is unlimited.
