Removing from a Set and Looping Over It in Swift

var colors = Set(["red", "blue", "green"])
colors.remove("blue")
colors.remove("pink")           // not in it, nothing happens

for color in colors {
    print(color)                // red and green, in any order
}

Full lesson:

s.remove(x) removes x from the set s. It returns the removed value. If x wasn't there, nothing happens and it returns nil.

for x in s visits each value of the set once. The order isn't fixed. Swift may even change it from one run to the next.

So loop over a set when the order doesn't matter. A total, a count and a check are fine.

Your task

In a word game, the set found holds the words a player found. The words "qqq" and "zzz" aren't allowed. Remove both from found.

The player never found "zzz", so removing it changes nothing.

Then add up the points. A word scores one point per letter. Loop over found and add each word's length to score.

The code already prints how many words are left, and the points.

Expected output:

4 words
14 points