TL ; DR:
A HashSet holds values without repeats. Inserting a value that is already in it changes nothing.
use std::collections::HashSet;
let mut pets: HashSet<&str> = HashSet::new(); // an empty set
pets.insert("cat");
pets.insert("cat"); // already in it, no change
println!("{}", pets.len()); // 1
println!("{}", pets.contains("cat")); // true
Full lesson:
A Vec keeps every value you put in it, repeats too. Sometimes you only need to know which values there are. A set is made for that.
A set holds each value once. Inserting a value that is already in it changes nothing.
HashSet comes from Rust's standard library. The use line at the top of the sample brings it in. Without it, the compiler doesn't know the name.
HashSet::new()makes an empty set. Declare it withlet mutto change it.s.insert(x)putsxin the sets. It returnsfalsefor a repeat.s.contains(&x)istruewhenxis in the set. It takes a reference.s.len()gives how many values the set holds.v.into_iter().collect()builds a set from the vectorv. Its repeats go in once.
As in Vec & Iterators, collect() needs the type after the name. Write let s: HashSet<&str> = ....
Checking s.contains(&x) is fast, even for a big set. A vector's contains looks at the values one by one.
A set has no order and no indexes. A printed set may show its values in any order.
Your task
The camp's sign-up vector, names, has some names twice. Build a HashSet named kids from it.
Then Zoe signs up, and Ava signs up again. Insert both names into kids.
Last, if kids contains "Leo", print Leo is coming.
The code already prints the number of kids twice.
Expected output:
3 kids
4 kids
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