TL ; DR:
Call map.contains_key(key) to ask whether a HashMap has a key. It returns true or false, so it goes in an if.
let capitals = HashMap::from([("France", "Paris"), ("Japan", "Tokyo")]);
if capitals.contains_key("Japan") {
println!("{}", capitals["Japan"]); // Tokyo
}
if !capitals.contains_key("Spain") {
println!("No Spain"); // No Spain
}
Full lesson:
Reading a missing key with [] panics. capitals["Spain"] stops the program.
So check first. capitals.contains_key("Spain") is true when "Spain" is a key. It is false when it isn't.
Put ! in front for the opposite. !capitals.contains_key("Spain") is true here.
A value is not a key
contains_key looks only at the keys. capitals.contains_key("Paris") is false, because "Paris" is a value.
When the key is a String in a variable, pass a reference, as in contains_key(&name).
A key must match exactly, upper and lower case too. capitals.contains_key("japan") is false.
Your task
In pets, each key is a pet's name, and its value is the pet's kind.
First, check whether "Tom" is a key of pets. If it is, print Tom is a followed by Tom's kind.
Then check that "cat" is not a key, with ! and contains_key. If so, print cat is not a key.
"cat" is in pets, but only as a value. It is Tom's kind.
Expected output:
Tom is a cat
cat is not a keyFree plan: 30 tutor messages. PRO is unlimited.
