TL ; DR:
Call map.contains(key) to ask whether a Map has a key. It returns true or false, so it goes in an if.
val capitals = scala.collection.mutable.Map("France" -> "Paris", "Japan" -> "Tokyo")
if (capitals.contains("Japan")) {
println(capitals("Japan")) // Tokyo
}
if (!capitals.contains("Spain")) {
println("No Spain") // No Spain
}
Full lesson:
Reading a missing key is an error. capitals("Spain") throws a NoSuchElementException.
So check first. capitals.contains("Spain") is true when "Spain" is a key. It is false when it isn't.
Put ! in front for the opposite. !capitals.contains("Spain") is true here.
A value is not a key
contains looks only at the keys. capitals.contains("Paris") is false, because "Paris" is a value.
A key must match exactly, upper and lower case too. capitals.contains("japan") is false.
Your task
In pets, each key is a pet's name, and its value is the pet's kind.
First, check whether "Tom" is a key of pets. If it is, print Tom is a followed by Tom's kind.
Then check that "cat" is not a key, with ! and contains. If so, print cat is not a key.
"cat" is in pets, but only as a value. It is Tom's kind.
Expected output:
Tom is a cat
cat is not a keyFree plan: 30 tutor messages. PRO is unlimited.
